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The hybridisation of atomic orbitals of nitrogen in $NO_2^{+},NO_3^{-}$ and $NH_4^{+}$ are

$(a)\;sp,sp^2\;and\;sp^3\;respectively \\ (b)\;sp,sp^3\;and \;sp^2\;respectively \\(c)\;sp^2,sp\;and\;sp^3\;respectively \\(d)\;sp^2,sp^3\;and \;sp\;respectively $

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The shapes of $NO_2,NO_3$ and $NH_4^{+}$ are linear, trigonal planar and tetrahedral , respectively.
Thus the hybridisation of atomic orbitals of nitrogen in these species are $sp,sp^2\;and\;sp^3$ respectively .
Hence a is the correct answer.
answered Apr 1, 2014 by meena.p
 

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