Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The cyanide ion, $CN^{-}$ and $N_2$ are isoelectronic . But in contrast to $CN^{-},N_2$ is chemically inert, because of

$(a)\;\text{$\pi$ bonding} \\ (b)\;\text{absence of bond polarity} \\(c)\;\text{unsymmetrical electron distribution } \\(d)\;\text{Presence of more number of electrons in bonding orbitals} $

Can you answer this question?

1 Answer

0 votes
Both $CN^{-}$ and $N_2$ molecules have the same $MO$ diagrams but differ only in bond polarity.
$CN^{-}$ ion is reactive due to presence of bond polarity.
While $N_2$ is inert due to absence of bond polarity.
Hence b is the correct answer.
answered Apr 1, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App