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Among the following compounds the one that is polar and has the central atom with $SP^2$ hybridisation is :

$(a)\;H_2CO_3 \\ (b)\;SiF_4 \\(c)\;BF_3 \\(d)\;HClO_2 $

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Carbon in $H_2CO_3$ has $sp^2$ hybridisation and also polar.
$BF_3$ has $sp^2$ but non-polar.
$SiF_4$ has $sp^{3}$ hybridisation, $HClO_2$ has $sp^3$ hybridisation.
Hence a is the correct answer.
answered Apr 1, 2014 by meena.p
 

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