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In piperidine N-atom has hybridisation

$(a)\;sp \\ (b)\;sp^2 \\(c)\;sp^3 \\(d)\;dsp^2 $
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N in piperidine has three $\sigma$ bond and one lone pair of electrons, hence N is $sp^3$ hybridised.
Hence c is the correct answer.
answered Apr 1, 2014 by meena.p

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