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Home  >>  CBSE XI  >>  Math  >>  Conic Sections
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Find the equation of the parabola that satisfies the given conditions: Focus $(0,-3)$ and Directrix $y=3$

$\begin{array}{1 1}x^2 = -12y \\ x^2 = 12y \\ y^2 = -12x \\ y^2 = 12x \end{array} $

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Given Focus $(0,-3)$ and Directrix $y=3$
Since the Focus is on the y-axis $\rightarrow$ this is the axis of the parabola.
The Directrix $y=3$ is above the x-axis while the focus is below the x-axis. Therefore the parabola is of the form $x^2=-4ay$
Therefore, this is of the type $x^2 = -4ay \rightarrow a = 3$
Therefore the equation of the parabola is $x^2 = - 4 \times 3 y = -12 y$
answered Apr 1, 2014 by balaji.thirumalai
edited Apr 11 by meena.p
 

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