logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  CBSE XI  >>  Math  >>  Conic Sections
0 votes

Find the equation of the parabola that satisfies the given conditions: Vertex $(0,0)$ and Focus $(3,0)$

$\begin{array}{1 1} y^2=12 x \\ x^2=-12y \\ y^2=-12x \\ x^2=12y \end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Given Vertex $(0,0)$ and Focus $(3,0)$
Since the vertex is the origin and the focus lies on the positive x-axis, $\rightarrow $ x-axis is the axis of the parabola.
The parabola is of the form $y^2=4ax$.
Since Focus = $(3,0) \rightarrow a = 3$
Therefore the equation of the parabola is $y^2 = 4 \times 3x = 12x$
answered Apr 1, 2014 by balaji.thirumalai
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...