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The electronegativities of $F,Cl,Br$ and $I$ are $4.0,3.0,2.8$ and $2.5$ respectively. Hydrogen halide with a high percentage of ionic character is

$(a)\;HF \\ (b)\;Hcl \\(c)\;HBr \\(d)\;HI $
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Greater is the electronegativity difference between x(halogen atom) and H; the greater is the ionic character.
Thus ionic character of $H-F$ is maximum.
Hence a is the correct answer.
answered Apr 2, 2014 by meena.p

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