$(a)\;2.237 : 2\qquad(b)\;2.237:1\qquad(c)\;2.237:3\qquad(d)\;2.237:4$

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For $H_2 : \mu_{AV} = \sqrt{(\large\frac{8R\times300}{\pi \times 2})}$

(Since T = 300 K and m.wt = 2 )

For $C_2H_6 : \mu_{AV} = \sqrt{(\large\frac{8R\times900}{\pi \times 30})}$

(Since T = 900 K and m.wt = 30 )

$\large\frac{\mu_{AV H_2}}{\mu_{AVC_2H_6}} = \sqrt{(\large\frac{300\times30}{900\times2})}$

= 2.237 : 1

Hence answer is (B)

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