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Which of the following have identical bond order? $(i)\; CN^{-} \\ (ii)\;NO_2^{-} \\ (iii)\;NO^{+} \\ (iv)\; CN^{+}$

$(a)\;\text{(i) and (iii) } \\ (b)\;\text{(i) and (iv)} \\(c)\;\text{(ii) and (iv) } \\(d)\;\text{(iii) and (iv)} $

1 Answer

Number of electrons in $O_2^{-}= 2 \times 8 +1=17$
Number of electrons in $NO^{+}= 7 + 8-1=14$
Number of electrons in $Cs_2= 6+2 \times 8 =22$
As $CN^{-}$ and $NO^{+}$ are isoelectronic , both have same bond order.
Hence a is the correct answer.
answered Apr 2, 2014 by meena.p
 

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