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There are 10 cinema tickets with seat number from 1 to 10 in a row. Ram and Shyam are friends and they do not want to be apart. If they are asked to randomly pick up their tickets, what is the probability for Ram and Shyam to sit next to each other?
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asked
Apr 2, 2014
by
balaji.thirumalai
retagged
Sep 10, 2014
by
sharmaaparna1
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The total number of choice is $P_{2,10} = 90.$
If they are to be sit together, the answer is $ 2 \times 9 = 18$
So the probability is $\large \frac{18}{90}$$ = \large\frac{1}{5}$.
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Apr 2, 2014
by
balaji.thirumalai
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