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Questions  >>  CBSE XI  >>  Math  >>  Conic Sections
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Find the equation of an ellipse that satisfies the following conditions: Length of major axis is $26$ and Foci is $(\pm5,0)$

$\begin{array}{1 1}\large\frac{x^2}{169}+\large\frac{y^2}{144}=1 \\ \large\frac{x^2}{169}+\large\frac{y^2}{25}=1 \\ \large\frac{x^2}{144}+\large\frac{y^2}{169}=1 \\ \large\frac{x^2}{25}+\large\frac{y^2}{169}=1 \end{array} $

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