Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The rate of the elementary reaction, $2NO+O_2 \to 2NO_2$ when the volume of the reaction vessel is doubled

$(A)\;\text{will grow eight times of its initial rate} \\ (B)\;\text{Reduce to one-eight of its initial rate } \\(C)\;\text{will grow four times of its initial rate } \\(D)\;\text{Reduce to one- fourth of its initial rate } $
Can you answer this question?

1 Answer

0 votes
$Rate =K[NO]^2[O_2]^1$
Concentration of each species are reduced by $\large\frac{1}{2}$ on increasing volume to two times and thus rate becomes $\large\frac{1}{8}$ time of initial rate .
Hence b is the correct answer.
answered Apr 3, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App