$(a)\;6.68 atm\qquad(b)\;0.5 atm\qquad(c)\;0.8 atm\qquad(d)\;0.66 atm$

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Given

Pressure of $N_2$ = 0.965 atm

Volume of $N_2$ = 10 litre

Temperature of $N_2$ = 298 K

For $N_2$ when bag is fully expanded ,

Volume of $N_2$ (alone) = 30 litre at 298 K

$\Rightarrow P_1V_1 = P_2V_2$

$\Rightarrow 0.965\times10 = P_2\times30$

$\therefore P_{N_2}$ (alone) in 30 litre bag at 298 K = 0.322 atm

Now

$P_M = P_{O_2} + P_{N_2}$

$ \Rightarrow 0.990 = P_{O_2} + 0.322$

$\Rightarrow P_{O_2}$ = 0.668 atm

Hence answer is (D)

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