Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

For a first order reaction , the plot of t against log C gives a straight with slope equal to :

$(A)\;\frac{K}{2.303} \\ (B)\;\frac{-K}{2.303} \\(C)\;\frac{ln K}{2.303} \\(D)\;\frac{-2.303}{K} $
Can you answer this question?

1 Answer

0 votes
For a first order reaction , $K_t=2.303 \log \bigg( \large\frac{a}{a-x}\bigg)$
or $t= \large\frac{2.303}{K}$$\log a - \large\frac{2.303 }{K}$$ \log (a-x)$
Thus slope $m= \large\frac{-2.303}{K}$
If $\log (a-x)=\log a -\large\frac{Kt}{2.303}$
Then slope is $\large\frac{-K}{2.303}$
Hence b is the correct answer.
answered Apr 3, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App