Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The rate of a reaction gets doubled when the temperature changes from $7^{\circ}C$ to $17^{\circ}$ . By what factor will it change for the temperature change from $17^{\circ}C$ to $27^{\circ}C$

$(A)\;1.81 \\ (B)\;1.71 \\(C)\;1.91 \\(D)\;1.76 $
Can you answer this question?

1 Answer

0 votes
$2.303 \log \large\frac{K_2}{K_1}=\frac{E_A}{R} \bigg[\large\frac{T_2-T_1}{T_1T_2}\bigg]$
$T= 280 \;K; T= 290\;K; \large\frac{K_2}{K_1} $$=2$
Find $E_a$ and then again use,
$2.303 \log \large\frac{K_2'}{K_1'}=\frac{E_A}{R} \bigg[\large\frac{T_2'-T_1'}{T_1'T_2'}\bigg]$
If $ T_1'=290\;K;T_2'= 300\;k$
Hence c is the correct answer.
answered Apr 3, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App