$(a)\;177^{\large\circ}C\qquad(b)\;108^{\large\circ}C\qquad(c)\;140^{\large\circ}C\qquad(d)\;150^{\large\circ}C$

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

Initial temperature = 300 K

Let no. of mole at 300K = n

Let new temperature be = T K

Mole coming out at T K = $\large\frac{1}{3} n$

Mole left at T K =$ n - \large\frac{1}{3}n$

$ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\; = \large\frac{2}{3}n$

Under constant P and V

$n_1T_1 = n_2T_2$

$n\times300 = \large\frac{2}{3}n\times T$

T = 450 K

$ = 177^{\large\circ}C$

Hence answer is (A)

Ask Question

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...

Why did you used the number of moles here??