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Home  >>  CBSE XI  >>  Math  >>  Limits and Derivatives
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Evaluate the following limits \[\] $ \lim\limits_{x \to 4} \large\frac{4x+3}{x-2}$

$\begin{array}{1 1}\large\frac{19}{2} \\ \large\frac{16}{3} \\ 19 \\ \large\frac{19}{3}\end{array} $

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$ \lim\limits_{x \to 4} \large\frac{4x+3}{x-2} $$ = \large\frac{4(4)+3}{4-2} $
$ \large\frac{16+3}{2}$
$ \large\frac{19}{2}$
answered Apr 3, 2014 by thanvigandhi_1
 

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