Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The rate law of a reaction $A+B \to $ product is rate $=K [A]^n[B]^m$. On doubling the concentration of A and halving the concentration of B. Thr ratio of new rate to the earlier rate of reaction will be :

$(A)\;n-m \\ (B)\;2^{n-m} \\(C)\;\large\frac{1}{2^{m+n}} \\(D)\;m+n $
Can you answer this question?

1 Answer

0 votes
$r_o=K [A]^n[B]^m$
$r_1= K[2A]^n[B/2]^m$
$r_1=Ke^{n-m} [A^n][B]^m$
$r_1=r \times 2^{n-m}$
Hence b is the correct answer.
answered Apr 3, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App