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If $ f(x)=\begin{vmatrix} x & x^2 & x^3 \\ 1 & 2x & 3x^2 \\ 0 & 2 & 6x \end{vmatrix}$ than find $ f' (x)$

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Toolbox:
  • Open the determinent and then differentiate.
$ f(x) = 2\: x^3$
$ f ' (x) = 6\: x^2$

 

answered Mar 12, 2013 by thanvigandhi_1
edited Mar 26, 2013 by thanvigandhi_1
 

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