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According to molecular orbitals theory which of the following statement about the magnetic character and bond order is correct regarding $O_2^{+}$?

$(A)\;\text{Paramagnetic and Bond order < O_2} \\ (B)\;\text{Paramagnetic and Bond order > O_2} \\(C)\;\text{Diamagnetic and Bond order < O_2} \\(D)\;\text{Diamagnetic and Bond order > O_2} $

1 Answer

$O_2^{+}$ has one unpaired electron and $O_2$ has two unpaired electrons.
Thus $O_2$ is more paramagnetic or $O_2^{+}$ is less paramagnetic.
The bond order of $O_2^{+}$ is $2.5$ and that of $O_2$ is 2.
Thus $O_2^{+}$ is paramagnetic and its bond order is greater than that of $O_2$
Hence b is the correct answer.
answered Apr 4, 2014 by meena.p
 

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