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# The molecularity of the reaction $6FeSO_4+3H_2SO_4+KClO_3 \longrightarrow KCl +3 Fe_2(SO_4)_3+3H_2O$ is

$(A)\;6 \\ (B)\;3 \\(C)\;10 \\(D)\;7$

$\qquad= 6+3+1=10$