Chat with tutor

Ask Questions, Get Answers


The rate of a gaseous reaction is given by the expression $k[A][B]$. If the volume of the reaction vessel is suddenly reduced to $ \large\frac{1}{4}$ th of the initial volume , the reaction rate relating to original rate will be

$(A)\;\frac{1}{10} \\ (B)\;\frac{1}{8} \\(C)\;8 \\(D)\;16 $

1 Answer

Since active mass = concentration in moles / litre.
Thus when the volume of the reaction vessel reduces to $\large\frac{1}{4}$th of its initial volume
The molar concentration of each reactant increases four times, Thus,
$r= K[4A][4B]$
$\quad= 16\;K[A][B]$
16 times
Hence D is the correct answer.
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.