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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class12  >>  Integral Calculus
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The integral $\Large \int \limits_{\normalsize 0}^{\normalsize \pi} $$ \sqrt{1 + 4 \sin^2\large\frac{x}{2} \normalsize- \normalsize 4 \normalsize\sin \large\frac{x}{2}}$$\;dx$

$\begin{array}{1 1} (A) \;\pi -4 \\ (B) \;\frac{2\pi}{3}-4-4\sqrt3 \\ (C) \;4\sqrt 3 - 4 \\ (D) \;4\sqrt 3 - 4-\large\frac{\pi}{3} \end{array} $

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