# A parallel plate capacitor is made of two circular plates separated by a distance of $5mm$ and with a dielectric of dielectric constant $2.2$ between them. When the electric field in the dielectric is $3 \times 10^4 \;V/m$, the change density of the positive plate will be close to

$\begin{array}{1 1}(A)\;3 \times 10^4 \;C/m^2 \\ (B)\;6 \times 10^4 \;C/m^2 \\(C)\;6 \times 10^{-7} \;C/m^2 \\(D)\;3 \times 10^{-7} \;C/m^2 \end{array}$

The change density of the positive plate will be close to $6 \times 10^{-7} \;C/m^2$
Hence C is the correct answer.