logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

Let $y= \tan^{-1}\bigg[\Large\frac{4x}{1+5x^2}\bigg] \normalsize +\tan^{-1}\bigg[\Large\frac{2+3x}{3-2x}\bigg],$ show that $ \Large\frac{dy}{dy}=\frac{5}{1+25x^2}$

Can you answer this question?
 
 

1 Answer

0 votes
Toolbox:
  • Write $\large \frac{4x}{1+5x^2}=\large\frac{5x-x}{1+5x^2}, \large\frac{2+3x}{3-2x}=\large\frac{\large\frac{2}{3}+x}{1-\large\frac{2}{3}x} $
  • $ tan^{-1}\large\frac{x-y}{1+xy}=tan^{-1}x-tan^{-1}y$
$ y = tan^{-1}5x-tan^{-1}x+tan^{-1}\large\frac{2}{3}+tan^{-1}x$
differentiate to get the answer.

 

answered Mar 9, 2013 by thanvigandhi_1
edited Mar 25, 2013 by thanvigandhi_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...