$\begin{array}{1 1}(A)\;\lambda_C=\lambda_{\infty}-(B)\sqrt C\\(B)\;\lambda_C=\lambda_{\infty}+(B)\sqrt C\\(C)\;\lambda_C=\lambda_{\infty}+(B)C\\(D)\;\lambda_C=\lambda_{\infty}-(B)C\end{array} $

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