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The equivalent conductance of NaCl at concentration C and at infinite dilution are $\lambda_C$ and $\lambda_{\infty}$ respectively.The correct relationship between $\lambda_C$ and $\lambda_{\infty}$ is given as : (where the constant B is positive)

$\begin{array}{1 1}(A)\;\lambda_C=\lambda_{\infty}-(B)\sqrt C\\(B)\;\lambda_C=\lambda_{\infty}+(B)\sqrt C\\(C)\;\lambda_C=\lambda_{\infty}+(B)C\\(D)\;\lambda_C=\lambda_{\infty}-(B)C\end{array} $

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$\lambda_C=\lambda_{\infty}-(B)\sqrt C$
Hence (A) is the correct answer.
answered Apr 7, 2014 by sreemathi.v
 

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