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The equivalent conductance of NaCl at concentration C and at infinite dilution are $\lambda_C$ and $\lambda_{\infty}$ respectively.The correct relationship between $\lambda_C$ and $\lambda_{\infty}$ is given as : (where the constant B is positive)

$\begin{array}{1 1}(A)\;\lambda_C=\lambda_{\infty}-(B)\sqrt C\\(B)\;\lambda_C=\lambda_{\infty}+(B)\sqrt C\\(C)\;\lambda_C=\lambda_{\infty}+(B)C\\(D)\;\lambda_C=\lambda_{\infty}-(B)C\end{array} $

1 Answer

Solution :
use $\lambda_c= \lambda_{\infty}- B \sqrt{C}$
this problem is based on Debye huckle equation $\lambda_C=\lambda_{\infty}-(B)\sqrt C$
The correct Answer is 3
From Debye Huckle equation we get,
$\lambda_c= \lambda_{\infty}- B \sqrt{C}$
Hence (A) is the correct answer.
answered Apr 7, 2014 by sreemathi.v
edited Oct 5 by meena.p

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