# In the reaction,$CH_3COOH\quad\underrightarrow{LiAlH_4}\quad A\quad\underrightarrow{PCl_5}\quad B\quad\underrightarrow {Alc.KOH}\quad C$,the product C is

$\begin{array}{1 1}(A)\;\text{Ethylene}\\(B)\;\text{Acetyl chloride}\\(C)\;\text{Acetaldehyde}\\(D)\;\text{Acetylene}\end{array}$

The product C is ethylene
Hence (A) is the correct answer.