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In the reaction,$CH_3COOH\quad\underrightarrow{LiAlH_4}\quad A\quad\underrightarrow{PCl_5}\quad B\quad\underrightarrow {Alc.KOH}\quad C$,the product C is

$\begin{array}{1 1}(A)\;\text{Ethylene}\\(B)\;\text{Acetyl chloride}\\(C)\;\text{Acetaldehyde}\\(D)\;\text{Acetylene}\end{array} $

1 Answer

The product C is ethylene
Hence (A) is the correct answer.
answered Apr 7, 2014 by sreemathi.v
 

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