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There is a circular tube in a vertical plane. Two liquids which do not mix and of densities $d_1$ and $d_2$ are filled int hetube. Each liquid subtends $90^{\circ}$ angle at centre. Radius joining there interface makes an angle $\alpha$ with vertical. Ratio $\large\frac{d_1}{d_2}$ is

$\begin{array}{1 1}(A)\;\large\frac{1+\tan \alpha}{1-\tan \alpha} \\ (B)\;\large\frac{1+\sin \alpha}{1- \cos \alpha} \\(C)\;\large\frac{1+\sin \alpha}{1- \sin \alpha} \\(D)\;\large\frac{1+\cos \alpha}{1-\cos \alpha} \end{array} $

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1 Answer

–1 vote
Ratio $\large\frac{d_1}{d_2}$ is $\large\frac{1+\tan \alpha}{1-\tan \alpha}$
Hence A is the correct answer.
answered Apr 7, 2014 by meena.p
 

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