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The correct set of four quantum numbers for the value electrons of rubidium atom (Z = 37) is

$\begin{array}{1 1}(A)\;5,1,1,+\large\frac{1}{2}\\(B)\;5,0,1,+\large\frac{1}{2}\\(C)\;5,0,0,+\large\frac{1}{2}\\(D)\;5,1,0,+\large\frac{1}{2}\end{array} $

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The correct set of four quantum numbers for the value electrons of rubidium atom (Z = 37) is $5,0,0,+\large\frac{1}{2}$
Hence (C) is the correct answer.
answered Apr 7, 2014 by sreemathi.v
 

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