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A block of mass $m$ is placed on a surface with a vertical cross section given by $y=\large\frac{x^3}{6}$. If the coefficient of friction is $0.5$, the maximum height above the ground at which the block can be placed without slipping is :

$\begin{array}{1 1}(A)\;\frac{1}{3}\;m\\ (B)\;\frac{1}{2}\;m \\(C)\;\frac{1}{6}\;m \\(D)\;\frac{2}{3}\;m \end{array} $

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The ground at which the block can be placed without slipping is :$\frac{1}{6}\;m$
Hence C is the correct answer.
answered Apr 7, 2014 by meena.p
 

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