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For complete combustion of ethanol $C_2H_5OH(l)+3O_2(g)\rightarrow 2CO_2(g)+3H_2O(l)$ the amount of heat produced as measured in bomb calorimeter,is 1$364.47\; kJ mol^{–1}$ at $25^{\large\circ}C$.Assuming ideality the Enthalpy of combustion,$\Delta_eH$,for the reaction will be: $(R = 8.314 kJ mol^{–1}$)

$\begin{array}{1 1}(A)\;–1460.50 kJ mol^{–1}\\(B)\;–1350.50 kJ mol^{–1}\\(C)\;–1366.95 kJ mol^{–1}\\(D)\;–1361.95 kJ mol^{–1}\end{array} $

1 Answer

$\Delta H_C=\Delta U_C+(\Delta n)_gRT$
$\Rightarrow -1364.47kJ+(-1)8.314\times 298J$
$\Rightarrow -(1364.47+2.48)kJ$
$\Rightarrow -1366.95kJ$
Hence (C) is the correct answer.
answered Apr 7, 2014 by sreemathi.v

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