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If $f$ and $g$ are differentiable function in $[0, 1]$ satisfying $f(0)=2 = g(1),g(0)= 0$ and $f(1)=6 $, then for some $c\in [0,1]$

$\begin{array}{1 1}(A)\;2f'(c)=g'(c)\\(B)\;2f'(c)=3g'(c)\\(C)\;f'(c)=g'(c)\\(D)\;f'(c)=2g'(c)\end{array} $

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$f'(c)=2g'(c)$
Hence (D) is the correct answer.
answered Apr 7, 2014 by sreemathi.v
 

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