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If $(10)^9+2(11)^1 (10)^8+ 3(11)^7+.....+10(11)^9=k(10)^9,$ then $k$ is equal to

$\begin{array}{1 1}(A)\;\large\frac{121}{10}\\ (B)\;\large\frac{441}{100} \\(C)\;100 \\(D)\;110 \end{array} $

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If $(10)^9+2(11)^1 (10)^8+ 3(11)^7+.....+10(11)^9=k(10)^9,$ then k is equal to $100$
Hence C is the correct answer.
answered Apr 7, 2014 by meena.p
 

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