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If $X= \{ 4^n-3n-1:n \in N\}$ and $Y=\{9(n-1):n \in N\}$. Where $N$ is the set of natural numbers , then $X \cup Y $ is equal to

$\begin{array}{1 1}(A)\;N \\ (B)\;Y-X \\(C)\;X \\(D)\;Y \end{array} $

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$X \cup Y $ is equal to$Y$
Hence D is the correct answer.
answered Apr 7, 2014 by meena.p
 
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