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# $\lim\limits_ {x \to 0} \large\frac{\sin (\pi \cos ^2 x) }{x^2}$ is equal to :

$\begin{array}{1 1}(A)\;\large\frac{\pi}{2} \\ (B)\;1 \\(C)\;-\pi\\(D)\;\pi\end{array}$

$\lim_ {x \to 0} \large\frac{\sin (\pi \cos ^2 x) }{x^2}$ is equal to : $\pi$
Hence D is the correct answer.