Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Let $a, b, c\; and \;d$ be non-zero numbers. If the point of intersection of the lines $4ax + 2ay + c = 0$ and $5bx+2by+d=0$ lies in the fourth quadrant and is equidistant from the two axes then

$\begin{array}{1 1}(A)\;2bc-3ad=0\\(B)\;2bc+3ad=0\\(C)\;3bc-2ad=0\\(D)\;3bc+2ad=0\end{array} $

Can you answer this question?

1 Answer

0 votes
Hence (C) is the correct answer.
answered Apr 7, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App