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Let PS be the median of the triangle with vertices P(2, 2), Q(6, –1) and R(7, 3). The equation of the line passing through (1, –1) and parallel to PS is

$\begin{array}{1 1}(A)\;4x-7y-11= 0\\(B)\;2x+9y+7=0\\(C)\;4x+7y+3=0\\(D)\;2x-9y-11=0\end{array} $

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1 Answer

The equation of the line passing through (1, –1) and parallel to PS is $2x+9y+7=0$
Hence (B) is the correct answer.
answered Apr 7, 2014 by sreemathi.v
 

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