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JEEMAIN-2014
Let PS be the median of the triangle with vertices P(2, 2), Q(6, –1) and R(7, 3). The equation of the line passing through (1, –1) and parallel to PS is
$\begin{array}{1 1}(A)\;4x-7y-11= 0\\(B)\;2x+9y+7=0\\(C)\;4x+7y+3=0\\(D)\;2x-9y-11=0\end{array} $
jeemain
jeemain-2014
math
q52
medium
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asked
Apr 7, 2014
by
sreemathi.v
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1 Answer
The equation of the line passing through (1, –1) and parallel to PS is $2x+9y+7=0$
Hence (B) is the correct answer.
answered
Apr 7, 2014
by
sreemathi.v
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