logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  CBSE XI  >>  Math  >>  Limits and Derivatives
0 votes

If the function $f(x)$ satisfies $ \lim\limits_{x \to 1} \large\frac{f(x)-2}{x^2-1}= \pi$ , evaluate $ \lim\limits_{x \to 1} f(x)$

Can you answer this question?
 
 

1 Answer

0 votes
$ \lim\limits_{x \to 1} \large\frac{f(x)-2}{x^2-1}= \pi$
$ \Rightarrow \large\frac{\lim\limits_{x \to 1}(f(x)-2)}{\lim\limits_{x \to 1}(x^2-1)}= \pi$
$ \Rightarrow \lim\limits_{x \to 1}(f(x)-2) = \pi \lim\limits_{x \to 1}(x^2-1)$
$ \Rightarrow \lim\limits_{x \to 1}(f(x)-2) = \pi (1^2-1)$
$ \Rightarrow \lim\limits_{x \to 1}(f(x)-2) = 0$
$ \Rightarrow \lim\limits_{x \to 1} f(x)- \lim\limits_{x \to 1} 2=0$
$ \Rightarrow \lim\limits_{x \to 1} f(x)- 2=0$
$ \therefore \lim\limits_{x \to 1} = 2$
answered Apr 7, 2014 by thanvigandhi_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...