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An atom of one element A has four electrons in its outermost shell, and that of B has six electrons in the outermost shell. The formula of the compound formed by these two will be

$(A)\;A_2B \\ (B)\;AB_2 \\(C)\;A_2B_3 \\(D)\;A_3B_2 $

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B completes its octet by sharing 2 electrons. A completes its octet by 4 electrons ,eg :$CO_2$
Hence B is the correct answer.
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