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The type of bonds present in $CuSO_4.5H_2O$ are only

$(A)\;\text{covelent and co-ordinate} \\ (B)\;\text{electrovalent and co-ordinate} \\(C)\;\text{electrovalent and covalent} \\(D)\;\text{electrovalent , covalent and co-ordinate} $

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A)
$Cu^{2+}$ and $SO_4^{2-}$ from ionic bond.
$SO_4^{2-}$ has covalent bonds and $H_2O$ shows co-ordinate bonds.
Hence D is the correct answer.

 

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