Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Let A and B be two events such that $P( \bar {P \cup B})=\large\frac{1}{6}$, $P(A \cap B)=\large\frac{1}{4}$ and $P(\bar {A})=\large\frac{1}{4}$, where $\bar {A}$ stands for the complement of the event A. Then the events A and B are :

$\begin{array}{1 1}(A)\;\text{mutally exclusive and independent}\\(B)\;\text{equally likely but not independent}\\(C)\;\text{independent but not equally likely}\\(D)\;\text{independent and equally likely}\end{array} $

Can you answer this question?

1 Answer

0 votes
The events A and B are independent but not equally likely
Hence C is the correct answer.
answered Apr 7, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App