$(a)\;54\;grams\qquad(b)\;27\;grams\qquad(c)\;108\;grams\qquad(d)\;270\;grams$

Thermodynamics

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Answer : $\;54\;grams$

Explanation :

Rate of heat flow = $\large\frac{KA (T_{1}-T_{2})}{L}$

$= \large\frac{0.16 \times 3 (300)}{20}$

$= 7.2 \;C.G.S.$ units

Heat transferred in 10 minutes

$=72 \times 10 \times 60$

$Q = 72 \times 60$

Let mass of ice melted be m

$Q = mL$

$72 \times 60 = m\times 80$

$m = 54 \;grams$

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