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If a,b and c are in A.P thin the straight line $ax+by+c=0$ will always pass through line $ax+by+c=0$ will always pass through a fixed point whose coordinates are

$\begin{array}{1 1}(A)\;(1,2) \\(B)\;(1,-2)\\(C)\;(1,1)\\(D)\;(1,3)\end{array}$

1 Answer

If a,b,c are in A.P then
=> $a-2b+c=0$
=> $ax+by+c=0$
it passes through $(1,-2)$
Hence B is the correct answer.
answered Apr 8, 2014 by meena.p

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