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Home  >>  CBSE XI  >>  Math  >>  Conic Sections
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Find the equations of the hyperbola satisfying the given conditions: Vertices: $(\pm 2, 0)$, Foci: $(\pm 3, 0)$

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Given Vertices: $(\pm 2, 0)$, Foci: $(\pm 3, 0) \rightarrow a = 2, c = 3$
Since $a^2+b^2 = c^2 \rightarrow b = \sqrt{9-4} = \sqrt {5} $
Therefore, the equation of the hyperbola is as follows: $\;\large\frac{x^2}{4}$$-\large\frac{y^2}{5}$$=1$
answered Apr 8, 2014 by balaji.thirumalai
 

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