logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  CBSE XI  >>  Math  >>  Conic Sections
0 votes

Find the equations of the hyperbola satisfying the given conditions: Vertices : $(\pm 7 )$, $e = \large\frac{4}{3}$

Can you answer this question?
 
 

1 Answer

0 votes
Toolbox:
Vertices : $(\pm 7 ) \rightarrow a = 7$
Given $e = \large\frac{4}{3}$$ \rightarrow \large\frac{4}{3}$$=\large\frac{c}{7}$$\rightarrow c =\large\frac{28}{3}$
Since $a^2+b^2 = c^2 \rightarrow b = \sqrt{ (\large\frac{28}{3})^2 \normalsize- \normalsize 49 \normalsize}$$ = \large\frac{\sqrt{343}}{3}$
Therefore, the equation of the hyperbola is as follows: $\;\large\frac{x^2}{49}$$-9\large\frac{y^2}{343}$$=1$
answered Apr 8, 2014 by balaji.thirumalai
edited Apr 8, 2014 by balaji.thirumalai
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...