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Coordinate Geometry
If one of the lines given by $6x^2-xy+4cy^2=0$ is $3x+4y=0$ then c equals
$\begin{array}{1 1}(A)\;-3\\(B)\;-1\\(C)\;3\\(D)\;1 \end{array}$
jeemain
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coordinate-geometry-straight-lines
equations-of-a-line
ch10
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asked
Apr 8, 2014
by
meena.p
retagged
Sep 26, 2014
by
sharmaaparna1
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1 Answer
$3x+4y=0$
is one of the lines of the pair.
$6x^2-xy+4cy^2=0$
Put $y=-\large\frac{-3}{4}$$x$
We get $6x^2+\large\frac{3}{4}$$x^2+4c\bigg(\large\frac{-3}{4}$$x^2 \bigg)=0$
=> $6+\large\frac{3}{4} +\frac{9c}{4}$$=0$
$c=-3$
Hence A is the correct answer.
answered
Apr 8, 2014
by
meena.p
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