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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Coordinate Geometry
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A straight line through the point $A(3,4)$ is such that its intercept between the axis is bisected at A. Its equation is

$\begin{array}{1 1}(A)\;x+y=7\\(B)\;3x-4y+7=0 \\(C)\;4x+3y=24 \\(D)\;3x+4y=25 \end{array}$

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1 Answer

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A is the mid point of PQ
$\large\frac{a+0}{2}$$=3=> a=6$
$\large\frac{0+b}{2}$$=4=> b=8$
Equation of the line is $\large\frac{x}{6}+\frac{y}{8}=1$
$\large\frac{4x+3y}{24}$$=1$
$4x+3y=24$
Hence C is the correct answer.
answered Apr 8, 2014 by meena.p
 

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