$(a)\;424.58\times10^2 Pa\qquad(b)\;424.58\times10^4 Pa\qquad(c)\;424.58\times10^5 Pa\qquad(d)\;424.58\times10^3 Pa$

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Equation for ideal gas,

$PV = \large\frac{w}{M}RT$

or $P = \large\frac{w}{V} \times \large\frac{RT}{M}$

$\;\;\; = d \times \large\frac{RT}{M}\;\;\; (\large\frac{w}{V} = density = d)$

Given

$d = 8.0 kg m^{-3} ; R = 8.314 JK^{-1}mol^{-1};$

$T = -40 + 273 = 233K$

And $M = 36.5 g mol^{-1} = 36.5\times 10^{-3}kg\;mol^{-1}$

Substituting the values in the above equation ,

$P = \large\frac{8.0\times8.314\times233}{36.5\times10^{-3}}$

$\;\;\;\; = 424.58\times10^3 Pa$

Hence answer is (D)

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