Ask Questions, Get Answers

Want to ask us a question? Click here
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Thermodynamics
0 votes

A wire of length 60 cm is bent into a circle with a gap of 1 cm at its ends . On heating by by $\;100^{0}C\;$ , If the length of the gap increases to 1.02 cm , $\;\alpha\;$ of the material of the wire is

$(a)\;2 \times 10^{-4}/^{0}C\qquad(b)\;4 \times 10^{-4}/^{0}C\qquad(c)\;6 \times 10^{-4}/^{0}C\qquad(d)\;1 \times 10^{-4}/^{0}C$

Can you answer this question?

1 Answer

0 votes
Answer : $\;2 \times 10^{-4}/^{0}C$
Explanation :
Arc length at $\;100^{0}C\;$ = Arc length at $\;0^{0}C\; [1+ \alpha \bigtriangleup t]$
$1.02 = 1 \;[1+ \alpha 100]$
$\alpha = 2 \times 10^{-4} /^{0}C$
answered Apr 8, 2014 by yamini.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App