$\begin{array}{1 1}91.4\; million\; miles \\94.56\; million\; miles \\ 92.96\; million\; miles \\ 93\; million\; miles \end{array} $

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According to Kepler, the planets follow an elliptical orbit, and the Sun is at the focus of the ellipse.

From the diagram above, the Sun is at one of the Foci, which means that the distance from the farthest point from Sun on the $x$-axis is $a + c = 94.56..... (1)$

By definition, eccentricity $e = \large\frac{c}{a} $$\rightarrow 0.017 = \large\frac{c}{a}$$ \rightarrow c = 0.017a$

Substituting in $(1)$, we get $1.017a = 94.56 \rightarrow a = 92.98$

$\Rightarrow c = 0.017a = 0.017 \times 92.98 = 1.58$.

Therefore the closest approach to the sun must be on the other side, closest to the focus, which is $92.98 - 1.58 = 91.4$ million miles.

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